Quick and dirty regexen search for spamd & postfix logs

#!/usr/bin/env python
#-------------------------------------------------------------
# Name:        finder.py
# Purpose:     This is a script to search through  Posfix 
#              and spamd logs for the last x days and return 
#              hits. Mostly it is a quick and dirty way to 
#              find entris regarding emails blocked by 
#              spamd/postfix   
# Author:      Reed L. O'Brien reed at reedobrien com
#                                                                                                           
# Created:     2007-01-05
# Modified:    2007-01-05
# Copyright:   (c) Reed L. O'Brien 2007
# License:     DWYWWI (improvements welcome)                         
#--------------------------------------------------------------                      


#Do the imports
import os, re, bz2, sys, time

# make sure there is a regex
try:
    # compile the regex
  regx = re.compile(sys.argv[1], re.IGNORECASE)
except IndexError:
  print """
  usage:
         finder  [days back to search]

         ex: finder foobar 2
         will find all occurences of 'foobar' in the last 2
         days of spamd and maillog files.\n\tThe number of days
         is optional and defaults to 1 if not given."""
  sys.exit(0)

# empty list to store hits in
found = []

# move to the log directory
os.chdir('/var/log')
# Start a counter for the number counted
s = 0

#get and set days
try:
 days = int(sys.argv[2])
except:
 days = 1
# Get a list of qualifying files NOTE: you may need stat(x).[st_ctime|st_mtime] depending on your OS
L = [f for f in os.listdir('.')
   if os.stat(f).st_birthtime > time.time() - (days * 86400)
   and (f.startswith('spamd') or f.startswith('maillog'))]
# get a count of how many files to search
n = len(L)

# start a loop on the list
for f in L:
    # If it is a bz2 open it as a bz2 object
if (f.startswith('spamd') or f.startswith('maillog')) and f.endswith('2'):
 # tell em what is happening
   sys.stdout.write("\rsearching: %2s  remain %s                   " % (f,n))
   sys.stdout.flush()
        # set a line count
   c = 1
        # get a handle on the file
        handle = bz2.BZ2File(f)
        # iterate through the lines
        for line in handle:
        # if the regex is found
       if regx.search(line):
           # append the filename, line count and line content to the found list
           found.append("%-10s : %s\n%s" % (c, f, line))
                # increment the line count
           c += 1
       else:
           # or just increment the count if no regex match 
           c += 1
                # decrement the number of files remaining
           n -= 1  
                # increment the number of files searched
           s += 1

    ## DO the same as above as a regular file object if not a bz2 file SEE NOTES FOR last loop
if (f.startswith('spamd') or f.startswith('maillog')) and not f.endswith('2'):
   sys.stdout.write("\rsearching: %2s  remain %s                     " % (f,n))
   sys.stdout.flush()
   c = 1
   handle = open(f)
   for line in handle:
       if regx.search(line):
           found.append("%-10s : %s\n%s" % (c, f, line))
           c += 1
       else:
           c += 1
           n -= 1
           s += 1
                ##make some space to overwrite the sys.stdout text 
print '\n\n\n\n\n'
print 'Searched:', s # Print how many files were searched

#print the results from the found list.
for x in found:
print x